# 39 out of 49 Test Score

### What grade is 39 out of 49?

Total number of questions or points possible

### 79.59% C+

A score of 39 out of 49 on a test, assignment or class is a 79.59% percentage grade. 10 questions were wrong or points missed.

A 79% is a C+ letter grade. A letter grade C+ means satisfactory or average performance. The teacher may round up the 79.59% to a 80% for a B- letter grade.

The grade point equivalent to a C+ is a 2.3 GPA for this score. If rounding up to a B-, the GPA is a 2.7.

### Letter Grades for 49 question test

A+48 to 490 to 197.96 to 100.00
A46 to 472 to 393.88 to 95.92
A-45491.84
B+43 to 445 to 687.76 to 89.80
B41 to 427 to 883.67 to 85.71
B-40981.63
C+38 to 3910 to 1177.55 to 79.59
C36 to 3712 to 1373.47 to 75.51
C-351471.43
D+33 to 3415 to 1667.35 to 69.39
D31 to 3217 to 1863.27 to 65.31
D-301961.22
F0 to 2920 to 490.00 to 59.18

This easy grade calculator can be used for quickly determining the percentage, letter grade and GPA for any test, quiz or exam. It can also be used when calculating an overall score in a class. This page is pre-populated showing the results for the particular calculation 39/49 as a percentage and as a grade. You can access the default calculator here.

To use, input the total number of questions or maximum points available in the "Questions" field. Next either enter the number of correct or incorrect answers in the respective fields. You only need to enter one, the other one will calculate automatically. Your results will appear as you type.

The result will compute the score as a percentage, the letter grade for the score and the GPA for the letter grade. The calculator will also indicate when a score is within one percent of the breakpoint between letter grades where it is appropriate to round up the grade.

Additionally you will see a letter grading scale table which shows every letter grade available for the number of questions on the test. This table indicates the correct and incorrect ranges for each letter grade along with the percentage ranges. Note that on some tests, letter grades are skipped - this is not a mistake. This happens on tests with fewer questions as each question is worth a significant percent of the overall score and significantly moves the letter grade.

## FAQ's

### Is a 39 out of 49 a good grade?

A score of 39/49 equates to a C+. C+ isn't a bad grade, but it's not a good grade either. You're falling short of other students' performance with a C+. A C+ is a bit below the average for most high school students (B letter grades).

### Is a 39 out of 49 a C+ or a B- grade?

39 out of 49 is right on the border between a C+ and a B-. It's equal to a 79.59% which is technically a C+. Because it's only 0.41 percentage points away from a B-, your teacher may give you a break and award you a B-.

### How is a percentage calculated for 39 out of 49?

The math is pretty simple to determine the percentage grade on a test as it's simple division and multiplication. The ratio of correct to total number of questions can be expressed as a fraction
The fraction is converted into a decimal using correct answers as the numerator and total questions as the denominator. Divide the correct answers by total questions and you have the answer in decimal form.
correct answers ÷ total questions = decimal
Now to convert into a percent, multiply the decimal times 100. This is your answer.
decimal × 100 = percent answer
In this particular case, the formula for calculating the grade percent 39/49 is
39 ÷ 49 × 100 = 79.59%
On a 49 question test, if you miss 10 and get 39 right, you will have a 79.59%.

### How is a letter grade determined for 39 out of 49?

To determine the letter grade, we must make use of a letter grade scale lookup table. You can find one here.

Take the percentage calculated for the test and locate the corresponding range in the percent column. The letter grade for that row is the letter grade for this test.

For this score, we find our 79.59% is in the 77-79% range. This corresponds with the letter grade "C+". Thus, a 79.59% grade is a C+.